题目
编写一个函数,其作用是将输入的字符串反转过来。输入字符串以字符数组 s
的形式给出。
不要给另外的数组分配额外的空间,你必须原地修改输入数组、使用 O(1) 的额外空间解决这一问题。
示例 1:
输入:s = ["h","e","l","l","o"]
输出:["o","l","l","e","h"]
示例 2:
输入:s = ["H","a","n","n","a","h"]
输出:["h","a","n","n","a","H"]
提示:
1 <= s.length <= 105
s[i]
都是 ASCII 码表中的可打印字符
解答
- 双指针从最左边到最右边遍历交换元素,直至左指针索引值大于右指针索引值。C++实现如下:
class Solution {
public:
void reverseString(vector<char>& s) {
int n = s.size();//获取数组长度
int left = 0, right = n - 1;
char temp = 0;
while(left < right) {
temp = s[left];
s[left] = s[right];
s[right] = temp;//交换操作
left++;
right--; //指针移动
}
//最后的s即为结果,函数返回类型为void所以无需返回值
}
};